Consider the following reaction equation:
C2H4(g) + 3O2(g) \(\to\) 2CO2(g) + 2H2O(g)
The volume of CO2(g) produced at s.t.p when 0.05 moles of C2H4(g) was burnt in O2(g) is
[Molar Volume of gas = 22.4dm3
a
1.12dm3
b
2.24dm3
c
3.72dm3
d
4.48dm3
Explanation
Correct Option
bVideo Explanation
No video available
Post your Contribution
Share:
Discussions (4)

Ndionuka
9 years ago
the answer is B
NOTE THAT 1mol of C2H4 reacted to produce 2mol of CO2
therefore 0.05mol of C2H4 will react to produce (0.05 * 2)mol of CO2

MILIONAIRABOY
4 years ago
I will love to suggest that 1 mole of C2H4 requires 2 moles of CO2. That shows that we will need 0.1 mole of CO2 according to the reaction.
Then, it will be 0.1 * 22.4, which will definitely gives us 2.2 dm3.


