7
6
5
3
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We have shells (KLMN)
This shells contains subshells (SPDF)
This subshells contains orbitals
S has one orbital and can contain a maximum of two electrons
P has three orbitals and can contain a maximum of six electrons
D has five orbitals amd can contain a maximum of ten electrons
F has seven orbitals and can contain a maximum of 14 electrons
An element with 13 electrons has this configuration:
1s2 2s2 2px2 2py2 2pz2 3s2 3px1
The element has three shells
The first shell (k) has one subshell (s)
The second shell (L) has two subshells (s and p)
The third shell (m) has two subshells (s and p)
Therefore and element with 13 electrons has three 'S' subshells and two 'P' subshells
One S subshell has one orbital therefore three will have 3 orbitals
One p orbital has three orbitals so two would have six orbitals
But in the P subshell of the third shell note that only one orbital was used therefore the total number of orbitals for p in the electronic configuration of the element is 4 orbitals
3+4 =7
The answer is 3 orbital because 13 as an atomic number has an electronic configuration of 2,8,3 which has the shells K,L,M respectively so the number of shells is equal to 3
