Consider the following half-cell reactions.
Al(s) \(\to\) Al3+(aq) + 3e-
Cu2+(aq) + 2e- \(\to\) Cu(s)
The overall equation for the reaction is
a
Al(s) + Cu2+(aq) \(\to\) Al3+(aq) + Cu(s)
b
2Al(s) + Cu2+(aq) \(\to\) 2Al(aq) + Cu(s)
c
2Al(s) + 3Cu2+(aq) \(\to\) 3Cu(s) + 2Al3+(aq)
d
3Al(s) + 2Cu2+(aq) \(\to\) Cu(s) + 3Al3+(aq)
Explanation
Correct Option
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Anzyumoh
4 years ago
it should be more like
2Al+(s) = 2Al³+(aq) +6e-
3Cu²+(aq) + 6e- = 3Cu(s)
so that the 6e cancel out, and we have
2Al+(s) + 3Cu²+(aq) = 2Al³+(aq) + 3Cu(s)
