Consider the following ionic equation:
Cr\(_2\)O\(_7\)\(^{2-}\) + 14H\(^+\) + ne-  → 2Cr\(^{3+}\) + 7H\(_2\)O.
The value of n in the equation is_______?

Boggs

1 year ago

Indeed, it is quite accurate that (2 - 14 = -12). If we consider (12 = 6), it does not equate. Thus, we subtract 6 from the left-hand side, and that 6 represents the (n) we are meant to determine. Therefore, (6 = 6), now achieving balance.

asgeer gsu

9 years ago

because ; 7(-2)+12(+1)+n(-1)=2(+3)

.: =-14+14-n=6

n=0-6

n=-6

Clinton14589

1 year ago

I need explanation

solomonade

8 years ago

hmm quite correct

Emmy1234

9 years ago

it is c electron diff 6-3=3

asgeer gsu

9 years ago

d is the answer