The correct order of increasing boiling points of the following compounds C3H7OH, C7H16 and C4H10 is?
C3H7OH → C4H10 → C7H10
C4H10 → C7H16 → C3H7OH
C7H16 → C3H7OH → C4H10
C4H10 → C3H7OH → C7H16
Explanation
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Discussions (30)
option D is correct
what if you don't know the boiling point, another way to tackle it is looking or calculating the molecular masas it increase together with boiling piont C4H10=48
C3H7OH= 60
C7H16 = 100
so option d have the correct other
C4H10→C7H16→C3H7OH
Molecules with hydrogen bonding have higher boiling points due to Hydrogen bonding. But if the intermolecular bonding is the same,the molecule with the higher molecular weight will have the highest boiling point.
THE CORRECT OPTION IS A
The correct answer should be D
As the boiling points of the given hydrocarbons are
C4H10: -138 C
C3H7OH: 97 C
C7H16: 98.42 C
Where C- represents degree celsius
B is correct
Because going down a series boiling point increases and votality decrease ,solubility decreased
So ethanol has hydrogen bond so that mk it more soluble than both of the organic compounds
do u mean the jamb series is wrong with some of their answers. if that's the case do something.
