In the preparation of oxygen by heating KClO\(_3\) in the presence of MnO\(_2\), only moderate heat is needed because the catalyst acts by?
In the thermal decomposition of potassium chlorate ((KClO\(_3\) ), manganese(IV) oxide (MnO\(_2\)) acts as a catalyst. A catalyst functions by providing an alternative reaction pathway with a lower activation energy (the "energy barrier"). Because this barrier is lowered, more reactant particles possess sufficient kinetic energy to undergo successful collisions at a lower temperature, allowing the reaction to proceed efficiently with only moderate heat.
While option C is also a characteristic of catalysts, option D specifically explains how the catalyst enables the use of moderate heat rather than the high temperatures required for the uncatalyzed reaction
There is an explanation video available below.
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}