In the preparation of oxygen by heating KClO\(_3\) in the presence of MnO\(_2\), only moderate heat is needed because the catalyst acts by?

a

lowering the pressure of the reaction

b

increasing the surface area of the reactant

c

increase the rate of the reaction

d

lowering the energy barrier of the reaction

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Explanation

Correct Option
d

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Discussions (21)

Progressiveness
3 years ago

The answer to this question is wrong. The question demands the mechanism in which catalyst works which is by lowering energy barrier or activation energy. Having been that the question asks the effect of catalyst, then option would have been the right answer. But the question asks for how the catalyst works. Therefore option D is the viable answer.

Overwatch886
2 years ago

Catalyst act by lowering the energy barrier thereby increasing the rate of reaction. This means that the most suitable answer for this question is option D, lowering the energy barrier as that is the major work the catalyst performs.

favi34
5 years ago

The question is wrong because according to new school chemistry, manganese (iv)oxide acts as a catalyst,the reaction occurs at a lower temperature and acts at a much faster rate

vipdyv
2 years ago

the answer should be "d" cauae when the energy barrier is lowered the temperature needed to overcome that energy barrier will therefore be less

TrustMeee123
3 months ago

The correct answer should be option D. Catalysts increase rate of reaction by lowering the activation barrier

AminunALLAH
8 years ago

answer is C ==
moderate heat is needed becouse the catalyst (manganasedioxide mno2) act by increasing the rate of the reaction

maxxalbert
1 year ago

a catalyst lowers activation energy and alters the rate of a chemical reaction and not necessarily increasing the rate of a reaction

Aqui
1 year ago

the correct answer is D

This question is WRONG

D IS THE ANS

it is not correct the answer is d

KiddoFx1
2 years ago

the answer is lowering the energy barrier

Leohh
6 months ago

normally a catalyst increase the rate of a reaction but "here specifically" that doesn't work

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