Calculate the solubility in mol dm-3 of 40g of CuSO4 dissolved in 100g of water at 120°C?
[Cu = 64, S = 32, O = 16]
4.00
2.50
0.40
0.25
Explanation
Video Explanation
Post your Contribution
Discussions (30)

solubility = solute/solvent * 1000/molar mass
solute=40
solvent=100g of water
molarmass of CUSO4 = 64+32+(16*4) = 160
40/100 *. 1000/160 =2.5

or you can use the formula
To find in mol/dm3=mass divided by molar mass x 1000 divided by volume (ignore temperature)
To find in g/dm3= mass divided by volume x 1000 over 1

It's 100cm2 and not 100g,
So it is hence
Mass/molar mass ×1000/volume
40/[40+(14×2)+(16×6)=0.25
1000/100=10
Therefore 0.25×10=2.5

solubility = conc. * 1000/volume
= mass/molar mass * "
= 40/160 * 1k/ 100
= 1/4 * 10
= 2.5

solubility in m/dm3= solubility in mass/dm3/molar mass
find the molar mass of Cuso4 i.e = 64+32+16 x 4 = 160grams.
40/160 = 0.25x 100 = 25






