Correct Answer: Option C

Explanation

CaCO₃ + CaO \(\to\) 2CaO + 2CO₂

44gm of CO₃ is liberated by 100gm of CaCO₃

0.33gm of CO₂ will be liberated by \(\frac{100}{44}\) x 0.33

= 0.75 of CaCO₃

Amount of CaO = 1 - 0.75

= 0.25

% of CaO = \(\frac{0.25}{1} \times \frac{100}{1}\)

= 25%

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