Given that the molecular mass of iron is 56 and that of oxygen is 16, how many moles of iron(iii)oxide will be contained in 1kg of the compound?

a

25.0 moles

b

12.5 moless

c

6.25 moles

d

3.125 moles

e

0.625 moles

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c

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Iron(iii) oxide=Fe2O3
Mass of Fe2O3=(56×2)+(16×3)
=160g
Therefore, 1 mole=160g
x moles=1kg(1000 grams)
x moles=(1000×1)/160
=6.25 moles

Obembzz
3 years ago

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