Chemistry
JAMB 1985
An organic compound contains 72% carbon, 12% hydrogen and 16% oxygen by mass. The empirical formula of the compound is
-
A.
C8H22O3
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B.
C6H10O3
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C.
C12H12O
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D.
C6H12O
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E.
C3H6O
Correct Answer: Option D
Explanation
carbon = 72%, hydrogen = 12%, 16%
Dividing by the atomic weight we have for C = \(\frac{5}{1}\) = 6
H = \(\frac{12}{1}\) = 12
O = \(\frac{16}{16}\) = 1
Divide by the smallest number, we have = \(\frac{6}{1}\) = 6
H = \(\frac{12}{1}\) = 12
O = \(\frac{1}{1}\) = 1
The formula is C6H12O
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