The relationship between the velocity (U) of gas molecules and their relative molecular mass (M) is shown by the equation
U = (kM)\(\frac{1}{2}\)
U = (kM)2
U = \(\sqrt{\frac{k}{m}}\)
U = \(\frac{k}{m}\)
Explanation
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Discussions (8)
Pls review the question.i think the ans is D.
Velocity of a gas can also be seen as the rate of diffusion of a gas that is the speed in which the gas diffuses.and rate of diffusion of a gas is inversely proportional to the square root of the molecular mass of the gas i.e r~1/√m removing the prpportionality sign we have
R= k/√m or R =(k/m)½ which is opt D.
Note: Rate of diffusion(R) of gas is the same thing with velocity of the gas(U)
The answer is wrong 
The rate or speed should be inversely proportional to the density/RMM of that substance (from Graham's law of diffusion)
thus
r = k/√m ... but √m = m^1/2
thus;
r = k.m^-1/2
A is closer to the answer 
