How much of magnesium is required to react with 260cm3 of 0.5 M HCl? [Mg...

How much of magnesium is required to react with 260cm3 of 0.5 M HCl? [Mg = 24]

First write a balanced chemical equation to show the reaction

Mg + 2HCl → MgCl\(_2\) + H\(_2\)

1mole : 2 moles

From what we were given n = \(\frac{CV}{1000}\)

n = \(\frac{{0.5}\times{260}}{1000}\)

n = 0.13 mole

By Simple proportion,

1 mole of Mg → 2 moles of HCl

then x mole of Mg → 0.13mole of HCl

x = \(\frac{0.13}{2}\) = 0.065mole

Also recall that n = \(\frac{m}{M}\)

m = n x M

m = 0.065 x 24 = 1.56g

Therefore the mass of Magnesium required to react with 260cm3 of 0.5 M HCl is 1.56g

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