When sodium ethanoate is treated with a few drops of concentrated tetraoxosulphate(vi)acid. one of the products is
a
CH3COOH
b
CH3COOCH3
c
CH3COOC2H5
d
C2H5COOCH3
Explanation
Correct Option
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khamis1danja
9 years ago
the formular for sodiumethanoate is CH3COONa
CH3COONa + H2SO4 -----> CH3COOH + Na2SO4
Auguocy
3 years ago
2CH3COONa+H2SO4=2CH3COOH+Na2SO4
Sodium ethanoate will react with tetraoxosulphate VI acid to yield ethanoic acid and sodium tetraoxosulphate VI
