Correct Answer: Option A

Explanation

\(MnO_{{4}{(aq)}}\) has a charge of \(-1\)

Let the oxidation number of \(Mn\) in \(MnO_{{4}{(aq)}}\) be X

Recall, the oxidation number of \(O_{2}\) is \(-2\)

\(\therefore\) \(X + (-2\times 4) = -1\)

\(X - 8 = -1\)

\(X = +7\)

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