A solution is prepared by dissolving I .96g of H₂SO₄ in 250 cm³ of its solution. What is the concentration in moles per dm³?

precious_gift

9 years ago

H2SO4 = (2+32+64)= 98.

Mol of H2SO4 = 1.96/98 = 0.02mol

Conc. = mol × vol in dm³

Conc. = mol × (1000/vol in cm³)

Conc. = 0.02 × (1000/250)

Conc. = 0.08 mol/dm³

Mimie123

3 years ago

mass=1.96g
Molar Mass=(2+32+64)=98
mole=mass÷molar mass
mole=1.96/98=0.02
Volume in dm³=250/1000=0.25
Conc.=mole /volume
Conc.=0.02/0.25=0.08mol/dm³