What is the concentration (mol dm\(^{-3}\)) of a solution containing 28 g of potassium hydroxide per 100 cm\(^3\) of solution? (K=39; H=1; O=16)

**Step 1: Molar mass of KOH**
K = 39, O = 16, H = 1
Molar mass = 39 + 16 + 1 = **56 g/mol**.

**Step 2: Moles in 28 g**
\[
\frac{28}{56} = 0.5 \text{ mol}
\]

**Step 3: Volume in dm³**
100 cm³ = \(0.1\ \text{dm}^3\).

**Step 4: Concentration**
\[
\frac{0.5}{0.1} = 5.0\ \text{mol dm}^{-3}
\]

\[
\boxed{5.0}
\]

Myschool Nuel

1 year ago

Apologies please! Kindly note that the question has been reviewed and the solution provided in the explanation box. Do well to go through and assimilate as much as you can.
Thank you