An atom of element X has an electronic configuration of \( 1s^22S^22p^63s^23p^3. \) In which group of the periodic table is X?

CalebOgbike

5 years ago

The Groups of an element are found by adding the number of electrons of the orbital with the highest principal quantum number. IN this case, 3s2 and 3p2. Therefore, 2+2 is equal to 4

etisiessence

2 years ago

It is incorrect

AceA001

1 year ago

1s2 2p3 3s2 3p2. Atomic number of Fluorine 9
Group 7, period 2, ionic number - 1

Myschool please make corrections.

feranmiadam

3 years ago

this question is making my question to ask questions 🧐

Kasibrown575857

5 years ago

The options are wrong,it ought to b group 7,pls my school do something abt it

ZiiUno

4 years ago

The question doesn't even make sense😂😂😂

SalawuSodiq

7 years ago

Dat Element(neon) Belong To Group 2,to Confirm It Possess Only 2 Bond

markkdman

9 years ago

i dont understand

Georgekome

1 year ago

The element is Flourine. It is group 7. No answer.

MansurMahdi

3 years ago

no answer

Enoglochidi

3 years ago

The electronic configuration is not correct

JATMAC

5 years ago

the question isn't correct

Anoibby

3 years ago

My school oo pls always give an explanation for your answers you don't expect us to cram answers we need to know why that was the answer

odesiri

2 years ago

the Question is wrong ooo my school

innotechkomputaz

8 years ago

1s2 2p3 3s2 3p2
Group 2