What mass of silver is deposited when a current of 2.6 A is passed through a solution of a silver salt for 40 minutes? [Ag= 108 ; F=96500C]

Sheezyola

1 year ago

The formula is
Mass=molar mass*Current*time/no of charge *Faraday constant.
now to shorten it M=MM*I*t/n*f
the charge for silver is +1
F=96500c
convert 40 mins to secs=40*60=2400secs
M=108*2.6*2400/1*96500
673920/96500
=6.98g
c is correct.