The molar mass of a compound X is 56. its empirical formula is CH2. X is
\((CH_{2})x = 56\)
\((12 + 2)x = 56\)
\(14x = 56\)
\(x = \frac{56}{14}\)
\(x = 4\)
Hence, the empirical formula is \((CH_{2}) \times 4\)
= \(C_{4}H_{8}\)
Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}