20 cm3 of 0.09 mol dm3 solution of tetraoxosuiphate (Vi) acid requires 30cm3 of sodium hydroxide solution for complete neutralization. The molar concentration of sodium hydroxide is [H = 1; S = 32; 0 = 16; Na = 23]
a
0.03 mol dm3
b
0.12 mol dm3
c
0.27 mol dm3
d
0.45 mol dm3
e
0.90 mol dm3
Explanation
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Mercy1305
7 years ago
Since we are given the volume(cm^3), and concentration of acid(mol dm^3) used and the volume of d base to b 30cm^3. The nxt thing is to calculate the mole ratio of the two solutions.
H2SO4 + 2NaOH = Na2SO4 + 2H2O
1 2
Since the reaction is of neutralization. Next thing is to apply your formula which is
CaVa/CbVb = mol ratio
where Ca =acid conc.
Va = vol. of acid.
Cb = conc. of base.
Vb = vol. of base.
Ca = 0.09 mol dm^3, Va = 20cm3, Cb= ? , Vb = 30cm3.
0.09*20/ Cb*30 = 1/2
make Cb the subject of d formula.
Cb = 2*0.09*20/30
> Cb = 0.12moldm^3
