CuO(s) + H\(_2\)(g) ↔ Cu(s) + H\(_2\)O(g) What is the effect of increasing the pressure...

JAMB 2009

CuO(s) + H\(_2\)(g) ↔ Cu(s) + H\(_2\)O(g)
What is the effect of increasing the pressure on the equilibrium reaction above?

A. The equilibrium is shifted to the left
B. The equilibrium is shifted to the right
C. There is no effect
D. More H_2(g) is produced

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Correct Answer: Option C

Explanation

When amount / volume of gaseous reactants equal amount / volume of gaseous products, the change in pressure has no effect on the equilibrium position.

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CuO(s) + H\(_2\)(g) ↔ Cu(s) + H\(_2\)O(g) What is the effect of increasing the pressure...

Correct Answer: Option C

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