What volume of 1.5M solution of KOH would contain 0.045 moles

Wawaaaaaaaaaaaqa

2 years ago

concentration = 1.5
no of moles = 0.045
volume = ?
CV=n
V= n/C
0.045/1.5 = 0.03dm^3
1000cm^3 =1dm^3
xcm^3 = 0.03dm^3
cross multiply
= 30cm^3

Atuchi

11 years ago

In details here

molar mass of KOH=56g

1.0M of 1000cm^3 comtains 56g of KOH.

Therefore 1.5M of 1000cm^3 will contain 84g of KOH (calculations is if 1M=56g den 1.5M= xg. Cross multiply xg=56g * 1.5=84g)

to get the volume that would contain 0.045moles is if 1.5M =1000cm^3 den 0.045M=xcm^3

xcm^3 = 1000 * 0.045 / 1.5

final answer is x=30cm^3

Anela

1 year ago

n= CV/1000
n=0.045
C=1.5

=0.045 = 1.5V/1000
CROSS MULTIPLY ✖️
0.045x1000 = 1.5V
=45=1.5V

DBS BY 1.5
V= 45/1.5
= 30(ANS)

darkypearl

12 years ago

aw s it B? is it nat C=nv? /n=cv.

usepassword

1 year ago

c*v=n*1000 1.5v=45 clt v=45÷1.5=30

Kamso005

2 years ago

you don't give detailed explanations

usepassword

1 year ago

n=c*v÷1000 cross multiply ❌ c**v