An oxidation state of Cr in K2Cr2O7

Nelson Dickson

9 years ago

K2Cr07 .(+1+2+X(-2x7)=0

+1+2+X-2x7=0

X=1x2-14=0

X=14/2=+7

Nelson Dickson

9 years ago

K=+1+2,Cr=X oxidation number of oxygen is -2(o-2) therefore.-; (-2x7)=-14. You will then say1x2=2.; 14/2=+7.. How do u see it guys?

udokaonyeaghala

10 years ago

una no fit compete with me for dis 1

JinmiBamidele JB

10 years ago

Definitely it is k2cr2o7^-2.

Tinker.bell

8 years ago

The chromium is meant to have a 2 just like oxygen having a 7 and potassium having a 2.
correct solution
+1*2+Cr2+2*-7
2+Cr2-14=0
Cr2=14-2
Cr2=12
divide both side by 2
Cr=+6

Finesse11

4 months ago

my school has given a explanation that is explanatory enough

ayomisesebere

5 years ago

The molecular formula given in the question is not total correct

Stephanielikita

1 year ago

I think the answer is A

big_raph

1 year ago

abeg can you people be explaining it well 😞

Najibutajo1

4 months ago

The Answer is +6

pettypumping

8 years ago

My school is disappointing me oo.. they should update their answers