An oxidation state of Cr in K2Cr2O7
The oxidation state of K2Cr2O7 is +6. option A,C,D are the oxidation state of other elements like O7,C14, etc.
\(+2 + 2x + (-2\times7) =0\)
\(2x=12\)
\(x = +6\)
There is an explanation video available below.
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