\(Cu_2S_{(s)}+ O_{2(g)} = 2CU_{(s)} + SO_{2(g)}\).

In the above reaction, the oxidation number of Cu changes from ___ to _______?

a

+1 to 0

b

0 to +2

c

+2 to +1

d

0 to +1

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Explanation

Correct Option
a

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Discussions (7)

ayomisesebere
5 years ago

The question is not well structured

Najibutajo1
4 months ago

2x -2 = 0
2x = 2
2x/2 = 2/2
x = 2/2
x = + 1
So it changes from +1 to 0

Officialovilla
4 years ago

Kinda critical

Johnbinary
1 year ago

change= change in product-change in reactants

oyindeeoluwadiya
2 years ago

Not complete

Emmanue1Tay0
1 year ago

There's no questions only a reaction

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