If a given quantity of electricity liberates 0.65g of Zn2+, what amount of Hg2+ would be liberated by the same quantity of current?
[Zn = 65, Hg = 201]

ibrahimawabch

10 years ago

g of zinc - 0.65. mass of zin 65

g of hg - x. mass of hg - 201



0.65/65 × x/201



0.65 × 201/65.

=2.01

Rocky2004

5 years ago

Molar mass of Zn=65
Molar mass of Hg=201
If 0.65g of Zn+ liberates 65g of Zn then 'x'g of Hg2+ will liberate 201
Therefore, 0.65=65
x= 201
Cross multiply
201*0.65=65*x
x= 201*0.65/65
x=2.01g
Ans=B

Nwachi.1

5 years ago

I mean it's not divalent

feranmiadam

3 years ago

ans is 2.01 not 2.10

mama8

3 years ago

since it is the same current that flows through them then: mass/molar mass =mass /molar mass
0.65/65=mass of hg/201
ans:2.01

Anela

1 year ago

m of Zn = 0.65
mm of Zn= 65
m of Hg = ?
mm of Hg=x
nF= 96500×2 = 193000(both are divalent)
m/mm = Q(it)/nF
Use Zn to find Q,then substitute the value of Q u will get for Hg

= 0.65/65 = Q/193000
CROSS MULTIPLY ✖️
125450/65 = Q
Q=1930

NOW SUBSTITUTE THAT VALUE FOR Zn USING THESAME FORMULA

m/201 = 1930/193000
CROSS MULTIPLY ✖️
m=387930/193000
= 2.01(ANS)

This is the formula I used, it's long though but this was how I understood the question.U can still stick with the shorter ones to save time.
But grab the formula.Tnks

tyjesma

11 years ago

2.01 not 2.10 @ admin...

Nwachi.1

5 years ago

This is very wrong and the problem actually begins with teh question cos Hg is monovalent and not trivalent. It's meant to be Hg+ and that will give you 4.02