Calculate the mass of sodium hydroxide in 5.00 dm3 of a 0.125 mol dm-3 solution. [NaOH = 40 g mol-1]
a
0.0156 g
b
0.625 g
c
1.00 g
d
25.0 g
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Kay179
8 months ago
The answer is 25.0g
using the formula n=cv
Where n is the no of moles
c is the concentration in mol/dm^3
v is the volume in dm^3
n=0.125*5
n=0.625mole
Also n=mass/molar mass
when you cross multiply
mass=n*molar mass
mass=0.625*40
mass=25g


