If the electron configuration of an element is 1S\(^2\) 2S\(^2\)2P\(^5\), how many unpaired electron are there?

peter samson

9 years ago

the p orbitals can contain just 6 electrons..so 6-5=1..

SELF OPINION THOUGH

Myschool Kelly

10 years ago

Thanks for your contributions and observations. Correction has been made.

Emmaunite1

11 years ago

it's 1 oh

wilicent

11 years ago

1 is de ans

ultraawesome

11 years ago

The answer is 1 na.

Golden Jacobs

11 years ago

The ans is 1 oooooo

DrUche

11 years ago

Why not one(1) admin? It's definitely not 18!

candychic

12 years ago

it can never be 18 O_o

tundejesu1504

12 years ago

double option pls make a correction 2 dis

somoyeanu98@gmail.com

11 years ago

How can it be 18.it is 1 habba

johnnysixtus

11 years ago

The element is florin and it has only one unpired electron

exboyteesquare

12 years ago

Y should we hv 2 in double options

exboyteesquare

12 years ago

Y should we have 2 in double options

Ruttie96

11 years ago

Maybe They Made Mistake By Adding 8 To The 1 To Make 18.

orimisan sunday

11 years ago

i think d ans is 1 not 18 bcos d atomic 9 and it ned only one to compt it shel