The oxidation state of oxygen in tetraoxosulphate (VI) acid is

maxmcfonsi

1 year ago

Very correct.

even the rules said the oxidation number of oxygen is always -2, except in Perioxides where it is -1.

no need for calculation sef.
but if you want to calculate, remember the acid is Tretaoxosulphate(vi) , meaning Sulphur used oxidation number of +6 in this reaction and not -2 (Sulphur can either lose 6 electrons or gain 2 to complete it's octet structure)

Eichiejohn

3 years ago

oxygen usually has oxidation state of -2 in its compounds expect in peroxides (-1) and superoxides(-½)

talk2kb

2 years ago

Trick Question no need of calculation
the Question is just asking avout Oxidation Number of Sulphur which is -2 …

Ozny

4 years ago

pls is sulphur not meant to be -2 and not 6

Ozny

4 years ago

is sulphur not meant ti be -2 and not 6

Bankz250

5 years ago

Mysch the answer is D

DrUche

6 years ago

Pls oo, does the solving shown above by myschool admin which is correct not mean that the oxidation state of Oxygen is -8? If x=-2 the 4*-2 = -8
That is, H= 2, S= 6 and O= -8 which brings the compound to a summation of zero
H(2)+S(6)+O(-8) = 0. That is option D.