Chemistry
JAMB 2007
Calculate the number of moles of HCl present in 20cm
3 of a 0.75M solution of the acid
-
A.
0.015 mole
-
B.
0.038 mole
-
C.
3.800 moles
-
D.
1.500 moles
Correct Answer: Option A
Explanation
Number of moles = (conc. in mol/dm
3*volume in cm
3)/1000
(0.75 * 20)/100 = 0.015 mole
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