a decrease in the free energy of the solution
a decrease in the entropy of the solution
a lowering of the temperature of te solution
an increase in the entropy of the solution
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Okay let's get this straightened up.
We were asked for the result of dissolving Naoh pellets in water. Now we all know that dissolving Naoh pellets in water is an exothermic reaction BUT that's not the direction this question is going. Let me explain further
NAOH pellets are solid substances. Dissolving them in water will make a transition from solid to liquid.
Now, we all know entropy is degree of disorderliness and is highest in gaseous substances. i.e Entropy increases from solid to liquid to gas and decreases the other way round.
The question is just there to test your knowledge of what you know.
Another thing you should note is that the value of Delta H (enthalpy) will be given concerning any question that deals with endothermic or exothermic reactions. Let your mind be at rest and don't be misled by Jamb.
Gracias ✅

When NaOH dissolves into water, it dissociates into two ions: a positively charged sodium ion and a negatively charged hydroxide ion (OH-). The increased number of hydroxide ions in the solution increases the concentration of hydroxide ions in the water.

Its "A"
The temp. of the solution will increase making the TΔS value more negative, and free energy =ΔH-TΔS, so the free energy is lesser

The answer is B
Reason:
If heat is evolved, ∆S is negative and there is a decrease in entropy.

