The number of sulphur atoms in 3.20g of SO\(_{2(g)}\) is [O = 16.0;S = 32.0; Avogadro constant = 6.02 x 10\(^{23}\)]
3.01 x 1022
6.02 x 1022
6.02 x1023
1.20 x 1024
Explanation
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To find the number of sulfur atoms in 3.20g of SO2, we first need to calculate the number of moles of SO2. The molar mass of SO2 is the sum of the molar mass of sulfur (S = 32.0) and twice the molar mass of oxygen (O = 16.0), which equals 64.0 g/mol.
The number of moles of SO2 is given by the formula:
moles of SO2=molar massmass=64.0g/mol3.20g=0.05 mol
Since each molecule of SO2 contains one atom of sulfur, the number of moles of sulfur is also 0.05 mol.
The number of atoms is given by the formula:
Number of atoms=Number of moles×Avogadro’s constant
Substituting the values we have:
Number of S atoms=0.05 mol×6.02×1023 atoms/mol=3.01×1022 atoms
