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The number of sulphur atoms in 3.20g of SO\(_{2(g)}\) is [O = 16.0;S = 32.0;...

Chemistry
WAEC 2012

The number of sulphur atoms in 3.20g of SO\(_{2(g)}\) is [O = 16.0;S = 32.0; Avogadro constant = 6.02 x 10\(^{23}\)]

  • A. 3.01 x 1022
  • B. 6.02 x 1022
  • C. 6.02 x1023
  • D. 1.20 x 1024
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Correct Answer: Option A
Explanation

32g of sulphur = 64g / 6.02 x 10\(^{23}\) atoms of SO\(_2\)

xg of sulphur = 3.2g of SO\(_2\) 

: 1.6g of sulphur is present in 3.2g / 3.01 x 10\(^{23}\) atoms of SO\(_2\)  

 

 


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