Consider the redox reaction as represented by the following equation: 1_2(aq) + 2S₂O₃^2-_(aq) → 21^-_(aq) + S₄O₆^2-_(aq). Which of the species in the equation is reduced?

Myschool Paul

9 years ago

Thanks for your contributions, correction has been made.

sodjay

9 years ago

i want to be better in physics nd chemistry how may i do it?

TheLivingLegend01

3 years ago

The correct answer is C. I_{2}(aq).

In this reaction, I_{2} is reduced from an oxidation state of 0 to -1. This is because it gains electrons from the thiosulfate ion, S_{2}O_{3}^{2-}. The thiosulfate ion is oxidized from an oxidation state of +2 to +3.

The other options are not correct. S_{4}O_{6}^{2-} is not reduced in this reaction. It is the product of the oxidation of S_{2}O_{3}^{2-}. S_{4}O_{3}^{2-} is not a species in this reaction. I^{-} is not reduced in this reaction. It is the product of the reduction of I_{2}.

Dammy9064

10 years ago

D answer is c cos i2 is on d reactant side,,,moreover it isnt avin oxygen

ABUEDE

9 years ago

mistake ...the answer is C...I2 reduce to I-..

temiuel

10 years ago

(C)-is the right ans bcos 'I2' is reduced to I-