Which of the following gases are arranged in increasing order of diffusion rate? [H = 1 .0; C = 12; N = 14; O = 16; S = 32]

Kellydance

1 year ago

don't be confused
A is very correct sharp
why? the question says the rate of gases in increasing order i.e from the smallest to the biggest
NB: gases with large molar mass will diffuse less while those with small molar mass will diffuse faster
did you get that logic? i guess you did
so now get the molar mass of if all the compounds and arrange them from the biggest to the smallest
Then you will get A
if you still don't understand refer to your textbook or seek help immediately

TheLivingLegend01

3 years ago

The diffusion rate of gases is inversely proportional to their molar mass, which means that gases with lower molar mass will have higher diffusion rates.

To determine the increasing order of diffusion rate of the given gases, we need to arrange them in increasing order of their molar mass.

A. SO2 (64), O2 (32), NH3 (17), H2 (2)
B. H2S (34), NH3 (17), O2 (32), SO2 (64)
C. CO2 (44), N2O (44), O2 (32), SO2 (64)
D. NH3 (17), NO2 (46), N2 (28), CO2 (44)

Based on their molar mass, the correct increasing order of diffusion rate of the given gases is:

A. H2 (2), NH3 (17), O2 (32), SO2 (64)
B. NH3 (17), O2 (32), H2S (34), SO2 (64)
C. O2 (32), CO2 (44), N2O (44), SO2 (64)
D. NH3 (17), N2 (28), CO2 (44), NO2 (46)

Therefore, the correct option is D. (NH3, N2, CO2, NO2)

Sandkaf

3 years ago

my school the answer is d from the smallest to the biggest, according to graham's law of diffusion the smaller the rate of diffusion the faster it diffuses