The percentage by mass of calcium in Ca(OCI)2 is [Ca = 40.0; CI = 35.5; O = 16.0]

Perfectpeacelyn

4 years ago

Molar mass of Ca(OCl)2=40+(16×2)+(35.5×2)
=40+32+71=143
% mass of Ca=40/143×10=27.9 approximately 28%

SOLTC93

2 years ago

The answer is 27.97%

joshkje

2 years ago

the question is not complete

TheLivingLegend01

3 years ago

The molecular weight of Ca(ClO)2 is:

Ca: 1 × 40.0 = 40.0
Cl: 2 × 35.5 = 71.0
O: 2 × 16.0 = 32.0
Total molecular weight = 143.0

The mass of calcium in one mole of Ca(ClO)2 is:

Ca: 1 × 40.0 = 40.0
The percentage by mass of calcium in Ca(ClO)2 is:

(40.0 / 143.0) × 100% = 27.97%
Therefore, the percentage by mass of calcium in Ca(ClO)2 is approximately 28.0%, which is option A.

kinglanre

10 years ago

(40.0+35.5+16.0) =91.5....

therefore to find % of cu =

40/91.5 multiplied by 100...or..40 times 100 divided by 91.5

=43.71% approx 43.8%