Correct Answer: Option A

Explanation

Molar mass of \(Ca(OCl)_2\) = 40 + (16 + 35.5)x2 = 143

% by mass of calcium in the compound =\(\frac{mass  of  calcuim}{molar  mass  of  compound}\) x 100%

% calcium = \(\frac{40}{143} \times100\)

  = 27.98% = 28%

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