The volume of 0.25 moldm-3 solution of KOH that would yield 6.5g of of solid KOH on evaporation is (K = 39.0; o = 16.0; H = 1.00)

Oreoluwalove

3 years ago

Molar mass KOH = 39.1 + 16 + 1 = 56.1 g/mol

Mass of 0.25 mol KOH = 56.1 g/mol *0.25 mol = 14.025 g

1.0 dm³ 0.25 M KOH solution contains 14.025 g KOH

Volume that contains 6.5 g KOH = 6.5 g / 14.025 g/dm³ =0.463 dm³ or 463 mL.

TheLivingLegend01

3 years ago

The correct answer is A. 464.30 cm3.

To solve this problem, we need to use the following formula:
V = n/M

where:

* V is the volume of the solution
* n is the number of moles of KOH
* M is the molarity of the solution

We know that the molarity of the solution is 0.25 moldm-3 and that the mass of KOH is 6.5g. We can use the molar mass of KOH (56.1 g/mol) to calculate the number of moles of KOH:
n = \frac{m}{M} = \frac{6.5 \{ g}}{56.1 \{ g/mol}} = 0.116 \{ mol}

Now we can plug in the values of n and M into the formula to calculate the volume of the solution:


V = \frac{n}{M} = \frac{0.116 \{ mol}}{0.25 \{ moldm-3}} = 0.464 \{ dm-3} = 464.30 \{ cm3}

Therefore, the volume of 0.25 moldm-3 solution of KOH that would yield 6.5g of of solid KOH on evaporation is 464.30 cm3.

sherif8

8 years ago

explanation needed please

Ixora106

4 years ago

pls explanation oooo,i did guess wrk dat wz hw i got d ansa,i nid help oooo

Solojide

5 years ago

explaination needed please

simeonwisdom

2 years ago

No explanation

Occupy

4 years ago

Use solubility formula