Consider the reaction represented by the following equation: C\(_2\)H\(_2\) + yH\(_2\) → C\(_2\)H\(_6\). The value of y in the reaction is
C\(_2\)H\(_2\) + yH\(_2\) → C\(_2\)H\(_6\)
To balance the equation, we must have 2 carbon atoms on both sides and 6 hydrogen atoms.
On the LHS and RHS, carbon = 2 atoms.
On the LHS, Hydrogen = 2 + 2y.
On the RHS, Hydrogen = 6.
⇒ 2 + 2y = 6
2y = 4
y = 2.
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