What is the amount of magnesium that would contain 1.20 x 10²⁴ particles? [Mg = 24, Avogadro's constant = 6.02 x 10²³]

khurmpleet

9 years ago

One mole of Mg=6.02*10^23 particles

X mole of Mg =1.20*10^24 particles

Therefore x moles of Mg=1.20*10^24/6.02*10^23

The answer is 1.99 MOLES approximately 2 moles.

Jessiqua

3 years ago

1 mol of Mg 24=6.02x10^23
x=1.20x10^24
x=1.20x10^24 x 24 /6.02x10^23
=1.99 =2.0 mole

SoSoSplendy

5 years ago

so the 24 of mg is not needed?

dosmay

10 years ago

somehow should explaim this please ASAP