1s22s 22px12py 1
1s 2 2s 22px 22pyo
1s12s22px12py12pz1
1s 22s12px12py12pz1
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Discussions (11)
The correct answer is:
D. 1s² 2s¹ 2px¹ 2py¹ 2pz¹
When carbon is excited, one of the 2s electrons jumps to the empty 2pz orbital to promote hybridization (which is important in bonding, like in methane, CH₄).
Why Not the Other Options?
A. 1s² 2s² 2px¹ 2py¹ 
→ Still in the ground state (no excitation).
B. 1s² 2s² 2px² 2py⁰ → Incorrect, since all three p orbitals should have one electron in the excited state.
C. 1s¹ 2s² 2px¹ 2py¹ 2pz¹ → Wrong because one 1s electron is missing, which doesn't happen in normal excitation.
I hope you understand now 
.
This answer can NEVER be correct,A is correct because the 2s orbitals have to be filled first before we ent3r the 2p and subsequently the 2px,2py amd 2pz orbital thats now where and each of them must have atleast 1 electron before another one can be added.
What is all this.this ans is super wrong🙄🤦.pls oo make corrections d crt and is option A.
The question says when carbon is excited. In its ground state, the answer will be A.
This answer is very wrong. S orbital is supposed to be filled before p. Option A is correct
