What is the molecular formula of a compound with empirical CH₂O and vapour density of 90? [H = 1, C = 12, O = 16]

Halilu abdullahi

10 years ago

This is becouse vapour density *2 is equal to the real molar mass. As we all know that for finding the molecular formular we must divide the mass of sample by the mass of emphirical formular. So that 90*2 =180/30 =6*emphirical formular that is c6h12o6