In the electrolysis of CuSO\(_4\)(g) using platinum electrodes, the reaction at the anode is
a
4H+ + 4e- → 2H2
b
4OH- + 4e- → 2H2O + O2
c
2OH - 2e- → 2OH
d
2OH- + 2OH- → 2H2O + O2
Explanation
Correct Option
bVideo Explanation
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