Correct Answer: Option B

Explanation

During the electrolysis of an aqueous copper sulfate (CuSO\(_4\)) solution using platinum electrodes, copper ions (Cu\(^{2+}\)) are reduced to solid copper (Cu) at the cathode, and water (H\(_2\)O) is oxidized to oxygen gas (O\(_2\)) and hydrogen ions (H\(^+\)) at the anode. 

Here's a more detailed explanation:

• Cathode (Reduction): Copper ions (Cu\(^{2+}\)) from the solution migrate towards the cathode and gain two electrons (2e-) to form solid copper, which deposits on the electrode. 

  • Reaction: Cu\(^{2+}\)(aq) + 2e- → Cu(s) 

• Anode (Oxidation): Water molecules (H\(_2\)O) are oxidized at the anode, losing electrons and forming oxygen gas (O\(_2\)) and hydrogen ions (H+). 

  • Reaction: 4OH\(^-\) + 4e\(^-\)(l) → 2H\(_2\)O(g) + O\(_2\) 

There is an explanation video available below.

• What can i study with 155 score in science course? Answer this

  1 Answers   ·   Biology   ·   2 days ago
• what is the fluid in the eye calles? Answer this

  1 Answers   ·   Biological Science   ·   14 hours ago
• which school is the richest school in Nigeria? Answer this

  1 Answers   ·   1 day ago