How many molecules are there in 14 g of nitrogen at s.t.p.? [N = 14, Avogadro's constant = 6.02 x 10\(^{23}\) mol-1]
Given:
mass, m = 14g
Molar mass of N\(_2\) = 14 X 2 = 28g/mol
number of moles, n = ?
But n = \(\frac{m}{M}\) = \(\frac{14}{28}\)
n = 0.5 mole
Also, recall that Number of moles = \(\frac{Number of Molecules}{Avogadro number}\)
n = \(\frac{N}{L}\)
N = n x L
= 0.5 x 6.02 x 10\(^{23}\)
= 3.01 x 10\(^{23}\) molecules
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}