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2C\(_2\)H\(_2\)(g) + 5O\(_2\)(g) → 4CO\(_2\)(g) + 2H\(_2\)O(g) In the reaction above, the mass of carbon(IV)oxide...

Chemistry
JAMB 2006

2C\(_2\)H\(_2\)(g) + 5O\(_2\)(g) → 4CO\(_2\)(g) + 2H\(_2\)O(g)
In the reaction above, the mass of carbon(IV)oxide produced on burning 78 g of ethyne is
[C =12, O = 16, H = 1]

  • A. 264 g
  • B. 39 g
  • C. 352 g
  • D. 156 g
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Correct Answer: Option A
Explanation

                      2C\(_2\)H\(_2\)(g) + 5O\(_2\)(g) → 4CO\(_2\)(g) + 2H\(_2\)O(g)

                        2 moles                :            4 moles

    n = \(\frac{mass}{molar mass}\) = \(\frac{78}{26}\)

   If                  3 moles                :              6 moles 

                                                            n = \(\frac{m}{M}\)

                                                            m =  n x M 

                                                             m = 6 x 44

                                                             m = 264g

There is an explanation video available below.


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Explanation Video

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