Consider the reaction represented by the following equation: Zn_(s) + 2HCI_(aq) → ZnCI_2(aq) + H_2(g) what volume of hydrogen gas is produced at s.t.p. when 3.25 g of zinc reacts with excess dilute HCI? [Zn = 65, Molar gas volume at s.t.p. = 22.4 dm^-3]

1.12 dm³

2.24dm³

4.48dm³

8.96dm³

Correct Option

No explanation available

No video available

4 years ago

No in moles= mass/ Rmm
=3.25/ 65
=0.05mol
n=vol/molar gas vol at stp
0.05= X/22.4
X= 22.4 *0.05
=1.12dm³

ceoofwahala

20th June, 2026

Chemistry

2 comments

ASSAAS

20th June, 2026

English Language

5 comments

infinitehoaxx

21st May, 2026

Computer

4 comments

Consider the reaction represented by the following equation: Zn(s) + 2HCI(aq) → ZnCI2(aq) + H2(g) what volume of hydrogen gas is produced at s.t.p. when 3.25 g of zinc reacts with excess dilute HCI? [Zn = 65, Molar gas volume at s.t.p. = 22.4 dm-3]