Consider the reaction represented by the equation. 2NaHCO_3(s) \(\rightarrow\) 2Na₂CO _3(S) + CO _2(g) + H₂O_(g) what volume of carbon (IV)oxide at s.t.p is evolved when 0. 5 moles of NaHCO₃ is heated? [Molar volume = 22.4 dm³ at s.t. p]

1.12dm³

2.24dm³

5.6dm³

56.0dm³

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montty

10 years ago

The ans is C

From the reaction,

2moles of NaHCO3--1mole of CO2

But 1mole of any gas occupies 22.4dm3 at STP,let x be the volume when its 0.5mol therefore

2mol ---22.4dm3

0.5mol--x

Cross multiply

2x=0.5*22.4

2x=11.2

X=11.2/2

X=5.6 dm3

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Consider the reaction represented by the equation. 2NaHCO3(s) \(\rightarrow\) 2Na2CO 3(S) + CO 2(g) + H2O(g) what volume of carbon (IV)oxide at s.t.p is evolved when 0. 5 moles of NaHCO3 is heated? [Molar volume = 22.4 dm3 at s.t. p]

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Consider the reaction represented by the equation. 2NaHCO_3(s) \(\rightarrow\) 2Na₂CO _3(S) + CO _2(g) + H₂O_(g) what volume of carbon (IV)oxide at s.t.p is evolved when 0. 5 moles of NaHCO₃ is heated? [Molar volume = 22.4 dm³ at s.t. p]