If 20 cm3 of distilled water is added to 80cm 3 of 0. 50 mol dm-3 hydrochloric acid, the new concentration of the acid will be

Jemal

2 years ago

C1V1=C2V2.......C1=0.5, V1=80, V2=100(80+20), C2=?
0.5*80=C2*100
C2=40/100
C2=0.4
Appreciate abeg 🤭

Esse007

4 years ago

lol what is wrong with this my school ppl
you guys chose D as your answer but your working shows C as the answer
the answer is actually C tho
pls make adequate corrections

etebster

8 years ago

answer is c please make adequate corrections

abdullahadepoju

2 years ago

I thought there is no need to add 2 volumes of a solution in order to get one

Jackieblackbea

2 years ago

Please I need to be clarify on this solving

olami1600

3 years ago

why are you people like this, your solvings showed c as the answer but you chosed d.
please make sure you correct it as soon as possible

etisiessence

2 years ago

The worked answer gives different answer from the chosen answer

Abzah

2 years ago

The answer is 0.40 mol dm-3 not 2.00 mol dm-3

ifunanyaonuoha200

2 years ago

According to the explanation the answer is C not D

Giah14

2 years ago

Of what???